Linden, Indiana

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Linden is a town in Madison Township, Montgomery County, Indiana, United States. The population was 700 at the 2000 census.

Contents

History

Linden was platted by Joel Lee, William Hartman and Hiram Hughes in 1851.[3]

Geography

Linden is located at 40°11′19″N 86°54′12″W / 40.188695°N 86.903311°W / 40.188695; -86.903311.[4]

According to the United States Census Bureau, the town has a total area of 0.3 square miles (0.7 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 700 people, 302 households, and 202 families residing in the town. The population density was 2,703.8 people per square mile (1,039.5/km²). There were 321 housing units at an average density of 1,239.9/sq mi (476.7/km²). The racial makeup of the town was 98.14% White, 0.29% African American, 0.57% Native American, and 1.00% from two or more races. Hispanic or Latino of any race were 0.43% of the population.

There were 302 households out of which 34.1% had children under the age of 18 living with them, 54.0% were married couples living together, 7.9% had a female householder with no husband present, and 33.1% were non-families. 27.8% of all households were made up of individuals and 11.9% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.80.

In the town the population was spread out with 25.6% under the age of 18, 6.6% from 18 to 24, 31.0% from 25 to 44, 23.0% from 45 to 64, and 13.9% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 97.7 males. For every 100 females age 18 and over, there were 91.5 males.

The median income for a household in the town was $36,750, and the median income for a family was $41,696. Males had a median income of $32,955 versus $22,679 for females. The per capita income for the town was $16,733. About 3.9% of families and 5.0% of the population were below the poverty line, including 6.0% of those under age 18 and 8.4% of those age 65 or over.

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