Lynch, Nebraska

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Lynch is a village in Boyd County, Nebraska, United States. The population was 269 at the 2000 census. Lynch is located in northern Nebraska, between the Missouri and Niobrara Rivers.



Lynch is located at 42°49′47″N 98°27′56″W / 42.82972°N 98.46556°W / 42.82972; -98.46556 (42.829804, -98.465453)[3].

According to the United States Census Bureau, the village has a total area of 0.6 square miles (1.5 km²), all of it land.


As of the census[1] of 2010, there were 254 people, 132 households, and 76 families residing in the village. The population density was 476.2 people per square mile (185.5/km²). There were 177 housing units at an average density of 313.3/sq mi (122.0/km²). The racial makeup of the village was 96.28% White, 1.86% Native American, 0.37% Asian, and 1.49% from two or more races.

There were 131 households out of which 18.3% had children under the age of 18 living with them, 52.7% were married couples living together, 3.8% had a female householder with no husband present, and 39.7% were non-families. 38.2% of all households were made up of individuals and 22.1% had someone living alone who was 65 years of age or older. The average household size was 2.05 and the average family size was 2.63.

In the village the population was spread out with 21.2% under the age of 18, 3.3% from 18 to 24, 15.6% from 25 to 44, 31.2% from 45 to 64, and 28.6% who were 65 years of age or older. The median age was 51 years. For every 100 females there were 93.5 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the village was $25,333, and the median income for a family was $29,792. Males had a median income of $23,571 versus $24,583 for females. The per capita income for the village was $15,702. About 5.2% of families and 11.0% of the population were below the poverty line, including 22.0% of those under the age of eighteen and 8.0% of those sixty five or over.


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