Medina, Ohio

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Medina (pronounced /mɨˈdaɪnə/ is a city in Medina County, Ohio, United States. In 2009, CNNMoney named Medina the 40th best American city to live in.[3] The population was 25,139 at the 2000 census. The 2008 projected population was estimated at 26,380.[4] It is the county seat of Medina County.[5]



Medina is located at 41°8′9″N 81°51′51″W / 41.13583°N 81.86417°W / 41.13583; -81.86417 (41.135899, -81.864069).[6]

According to the United States Census Bureau, the city has a total area of 11.3 square miles (29.3 km²), of which, 11.1 square miles (28.8 km²) of it is land and 0.2 square miles (0.5 km²) of it (1.68%) is water.


As of the census[2] of 2000, there were 25,139 people, 9,467 households, and 6,683 families residing in the city. The population density was 2,259.4 people per square mile (872.1/km²). There were 9,924 housing units at an average density of 891.9/sq mi (344.3/km²). The racial makeup of the city was 94.60% White, 2.77% African American, 0.19% Native American, 0.74% Asian, 0.03% Pacific Islander, 0.26% from other races, and 1.41% from two or more races. Hispanic or Latino of any race were 1.00% of the population.

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