Meeteetse, Wyoming

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Meeteetse is a town in Park County, Wyoming, United States. The population was 351 at the 2000 census.



Meeteetse is located at 44°9′21″N 108°52′8″W / 44.15583°N 108.86889°W / 44.15583; -108.86889 (44.155954, -108.869022)[3].

According to the United States Census Bureau, the town has a total area of 0.8 square miles (2.1 km²), all of it land.


As of the census[1] of 2000, there were 351 people, 151 households, and 94 families residing in the town. The population density was 428.7 people per square mile (165.3/km²). There were 188 housing units at an average density of 229.6/sq mi (88.5/km²). The racial makeup of the town was 97.15% White, 0.28% Native American, 0.28% Pacific Islander, 0.85% from other races, and 1.42% from two or more races. Hispanic or Latino of any race were 2.56% of the population.

There were 151 households out of which 27.2% had children under the age of 18 living with them, 56.3% were married couples living together, 4.6% had a female householder with no husband present, and 37.1% were non-families. 32.5% of all households were made up of individuals and 15.9% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 3.00.

In the town the population was spread out with 24.8% under the age of 18, 5.4% from 18 to 24, 24.8% from 25 to 44, 28.5% from 45 to 64, and 16.5% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 106.5 males. For every 100 females age 18 and over, there were 95.6 males.

The median income for a household in the town was $29,167, and the median income for a family was $31,953. Males had a median income of $21,250 versus $18,125 for females. The per capita income for the town was $12,030. About 5.8% of families and 10.9% of the population were below the poverty line, including 11.6% of those under age 18 and 14.9% of those age 65 or over.

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