Midwest, Wyoming

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Midwest is a town in Natrona County, Wyoming, United States. It is part of the Casper, Wyoming Metropolitan Statistical Area. The population was 408 at the 2000 census.



Midwest is located at 43°24′30″N 106°16′41″W / 43.40833°N 106.27806°W / 43.40833; -106.27806 (43.408203, -106.278114)[3].

According to the United States Census Bureau, the town has a total area of 0.4 square miles (1.1 km²), all of it land.


As of the census[1] of 2000, there were 408 people, 149 households, and 101 families residing in the town. The population density was 922.0 people per square mile (358.0/km²). There were 228 housing units at an average density of 515.2/sq mi (200.1/km²). The racial makeup of the town was 95.34% White, 0.25% African American, 1.23% Native American, 1.96% from other races, and 1.23% from two or more races. Hispanic or Latino of any race were 2.70% of the population.

There were 149 households out of which 38.9% had children under the age of 18 living with them, 53.0% were married couples living together, 11.4% had a female householder with no husband present, and 32.2% were non-families. 26.2% of all households were made up of individuals and 13.4% had someone living alone who was 65 years of age or older. The average household size was 2.74 and the average family size was 3.33.

In the town the population was spread out with 33.6% under the age of 18, 5.4% from 18 to 24, 29.9% from 25 to 44, 22.1% from 45 to 64, and 9.1% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 105.0 males. For every 100 females age 18 and over, there were 99.3 males.

The median income for a household in the town was $30,000, and the median income for a family was $33,125. Males had a median income of $28,000 versus $20,625 for females. The per capita income for the town was $12,891. About 25.0% of families and 29.1% of the population were below the poverty line, including 45.0% of those under age 18 and 23.7% of those age 65 or over.

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