Monrovia, Indiana

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Monrovia is a town in Monroe Township, Morgan County, Indiana, United States. The population was 628 at the 2000 census.

Contents

Geography

Monrovia is located at 39°34′46″N 86°28′49″W / 39.57944°N 86.48028°W / 39.57944; -86.48028 (39.579389, -86.480402)[3].

According to the United States Census Bureau, the town has a total area of 0.9 square miles (2.3 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 628 people, 234 households, and 187 families residing in the town. The population density was 709.1 people per square mile (272.4/km²). There were 245 housing units at an average density of 276.6/sq mi (106.3/km²). The racial makeup of the town was 99.20% White, 0.16% from other races, and 0.64% from two or more races. Hispanic or Latino of any race were 0.96% of the population.

There were 234 households out of which 36.8% had children under the age of 18 living with them, 64.1% were married couples living together, 13.2% had a female householder with no husband present, and 19.7% were non-families. 16.7% of all households were made up of individuals and 5.6% had someone living alone who was 65 years of age or older. The average household size was 2.68 and the average family size was 2.97.

In the town the population was spread out with 25.3% under the age of 18, 10.0% from 18 to 24, 27.7% from 25 to 44, 26.3% from 45 to 64, and 10.7% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 86.4 males. For every 100 females age 18 and over, there were 81.8 males.

The median income for a household in the town was $49,583, and the median income for a family was $53,571. Males had a median income of $32,917 versus $21,111 for females. The per capita income for the town was $20,366. About 6.8% of families and 8.6% of the population were below the poverty line, including 14.4% of those under age 18 and 2.9% of those age 65 or over.

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