Moorcroft, Wyoming

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Moorcroft is a town in Crook County, Wyoming, United States. The population was 807 at the 2000 census.

Contents

History

The town was named after Alexander Moorcroft, an early settler.[3]

Geography

Moorcroft is located at 44°15′54″N 104°57′2″W / 44.265°N 104.95056°W / 44.265; -104.95056 (44.264863, -104.950663)[4].

According to the United States Census Bureau, the town has a total area of 1.1 square miles (2.8 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 807 people, 325 households, and 219 families residing in the town. The population density was 731.4 people per square mile (283.3/km²). There were 375 housing units at an average density of 339.9/sq mi (131.6/km²). The racial makeup of the town was 98.14% White, 0.99% Native American, 0.25% from other races, and 0.62% from two or more races. Hispanic or Latino of any race were 1.36% of the population.

There were 325 households out of which 34.5% had children under the age of 18 living with them, 56.0% were married couples living together, 7.7% had a female householder with no husband present, and 32.6% were non-families. 25.8% of all households were made up of individuals and 9.8% had someone living alone who was 65 years of age or older. The average household size was 2.48 and the average family size was 3.04.

In the town the population was spread out with 27.3% under the age of 18, 11.3% from 18 to 24, 27.4% from 25 to 44, 24.3% from 45 to 64, and 9.8% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 99.8 males. For every 100 females age 18 and over, there were 99.7 males.

The median income for a household in the town was $36,953, and the median income for a family was $41,484. Males had a median income of $32,109 versus $19,632 for females. The per capita income for the town was $16,476. About 2.6% of families and 5.2% of the population were below the poverty line, including 4.5% of those under age 18 and 7.2% of those age 65 or over.

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