Newton, Utah

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Newton is a town in Cache County, Utah, United States. It was founded in 1869 by LDS Pioneers of The Church of Jesus Christ of Latter-day Saints. The population was 699 at the 2000 census. It is included in the Logan, Utah-Idaho Metropolitan Statistical Area.

Contents

Geography

Newton is located at 41°51′40″N 111°59′24″W / 41.86111°N 111.99°W / 41.86111; -111.99 (41.861169, -111.989936).[3]

According to the United States Census Bureau, the town has a total area of 0.8 square miles (2.0 km²), all of it land.

History

Newton was first settled in 1869. A bridge was built over the Bear River in 1871 and it was at that point that many of the inhabitants of Clarkston, Utah moved to this "new town".[4]

Demographics

As of the census[2] of 2000, there were 699 people, 196 households, and 165 families residing in the town. The population density was 915.2 people per square mile (355.1/km²). There were 204 housing units at an average density of 267.1/sq mi (103.6/km²). The racial makeup of the town was 96.57% White, 2.29% Asian, 0.72% from other races, and 0.43% from two or more races. Hispanic or Latino of any race were 2.43% of the population.

There were 196 households out of which 53.1% had children under the age of 18 living with them, 77.6% were married couples living together, 4.1% had a female householder with no husband present, and 15.8% were non-families. 13.3% of all households were made up of individuals and 7.7% had someone living alone who was 65 years of age or older. The average household size was 3.57 and the average family size was 4.02.

In the town the population was spread out with 36.8% under the age of 18, 12.6% from 18 to 24, 22.0% from 25 to 44, 20.6% from 45 to 64, and 8.0% who were 65 years of age or older. The median age was 26 years. For every 100 females there were 105.6 males. For every 100 females age 18 and over, there were 106.5 males.

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