Parral, Ohio

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Parral is a village in Tuscarawas County, Ohio, United States. The population was 241 at the 2000 census.



Parral is located at 40°33′39″N 81°29′48″W / 40.56083°N 81.49667°W / 40.56083; -81.49667 (40.560929, -81.496529)[3].

According to the United States Census Bureau, the village has a total area of 0.2 square miles (0.5 km²), all of it land.


As of the census[2] of 2000, there were 241 people, 106 households, and 71 families residing in the village. The population density was 1,332.1 people per square mile (516.9/km²). There were 107 housing units at an average density of 591.4/sq mi (229.5/km²). The racial makeup of the village was 99.17% White and 0.83% from two or more races.

There were 106 households out of which 28.3% had children under the age of 18 living with them, 58.5% were married couples living together, 6.6% had a female householder with no husband present, and 32.1% were non-families. 27.4% of all households were made up of individuals and 9.4% had someone living alone who was 65 years of age or older. The average household size was 2.27 and the average family size was 2.78.

In the village the population was spread out with 22.4% under the age of 18, 2.1% from 18 to 24, 29.9% from 25 to 44, 29.0% from 45 to 64, and 16.6% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 113.3 males. For every 100 females age 18 and over, there were 114.9 males.

The median income for a household in the village was $35,833, and the median income for a family was $41,023. Males had a median income of $34,250 versus $12,361 for females. The per capita income for the village was $18,021. About 4.0% of families and 7.0% of the population were below the poverty line, including 3.5% of those under the age of eighteen and none of those sixty five or over.


In January 2008, the mayor was Mark DiGenova.[citation needed]


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