Ravenna, Nebraska

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Ravenna is a city in Buffalo County, Nebraska, United States. It is part of the Kearney, Nebraska Micropolitan Statistical Area. The population was 1,341 at the 2000 census.



Ravenna is located at 41°1′40″N 98°54′48″W / 41.02778°N 98.91333°W / 41.02778; -98.91333 (41.027700, -98.913347)[3].

According to the United States Census Bureau, the city has a total area of 0.8 square miles (2.0 km²), all of it land.


As of the census[1] of 2000, there were 1,341 people, 534 households, and 349 families residing in the city. The population density was 1,782.0 people per square mile (690.4/km²). There were 600 housing units at an average density of 797.3/sq mi (308.9/km²). The racial makeup of the city was 98.96% White, 0.15% Asian, 0.37% from other races, and 0.52% from two or more races. Hispanic or Latino of any race were 0.82% of the population.

There were 534 households out of which 32.4% had children under the age of 18 living with them, 55.4% were married couples living together, 7.7% had a female householder with no husband present, and 34.5% were non-families. 31.5% of all households were made up of individuals and 18.7% had someone living alone who was 65 years of age or older. The average household size was 2.39 and the average family size was 3.02.

In the city the population was spread out with 26.9% under the age of 18, 6.1% from 18 to 24, 26.1% from 25 to 44, 17.0% from 45 to 64, and 23.9% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 83.4 males. For every 100 females age 18 and over, there were 77.2 males.

The median income for a household in the city was $31,875, and the median income for a family was $39,609. Males had a median income of $31,111 versus $19,226 for females. The per capita income for the city was $15,953. About 3.7% of families and 7.6% of the population were below the poverty line, including 7.5% of those under age 18 and 13.7% of those age 65 or over.

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