Rockaway, New Jersey

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Rockaway is a borough in Morris County, New Jersey, USA. As of the United States 2000 Census, the borough population was 6,473.

Rockaway was formed as a borough on June 19, 1894, from portions of Rockaway Township, based on the results of a referendum held the previous day.[7]



Rockaway is located at 40°54′01″N 74°30′49″W / 40.900365°N 74.513557°W / 40.900365; -74.513557 (40.900365, -74.513557).[8] The borough has a total area of 2.1 square miles (5.5 km2), of which, 2.1 square miles (5.4 km2) of it is land and 0.04 square miles (0.1 km2) of it (0.95%) is water.


As of the census[4] of 2000, there were 6,473 people, 2,445 households, and 1,709 families residing in the borough. The population density was 3,098.9 people per square mile (1,195.8/km2). There were 2,491 housing units at an average density of 1,192.5/sq mi (460.2/km2). The racial makeup of the borough was 87.75% White, 1.41% African American, 0.20% Native American, 6.36% Asian, 0.03% Pacific Islander, 2.98% from other races, and 1.27% from two or more races. Hispanic or Latino of any race were 9.39% of the population.

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