Roosevelt, New York

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{household, population, female}
{mi², represent, 1st}

Roosevelt is a hamlet (and census-designated place) in Nassau County, New York, United States. The population was 15,854 at the 2000 census.

Roosevelt is in the town of Hempstead.

Contents

Geography

Roosevelt is located at 40°40′45″N 73°35′08″W / 40.679172°N 73.585471°W / 40.679172; -73.585471.[1]

According to the United States Census Bureau, the CDP has a total area of 4.6 km2 (1.8 mi²). 4.6 km2 (1.8 mi2) of it is land and 0.56% is water.

Demographics

As of the census[2] of 2000, there were 15,854 people, 4,061 households, and 3,362 families residing in the CDP. The population density was 3,438.9/km2 (8,916.8/mi2). There were 4,234 housing units at an average density of 918.4/km2 (2,381.3/mi2). The racial makeup of the CDP was 3.97% White, 79.02% African American, 0.46% Native American, 0.49% Asian, 0.05% Pacific Islander, 8.33% from other races, and 3.69% from two or more races. Hispanic or Latino of any race were 16.22% of the population.

There were 4,061 households out of which 38.3% had children under the age of 18 living with them, 44.2% were married couples living together, 30.3% had a female householder with no husband present, and 17.2% were non-families. 12.0% of all households were made up of individuals and 4.1% had someone living alone who was 65 years of age or older. The average household size was 3.88 and the average family size was 3.98.

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