Roseland, Kansas

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Roseland is a city in Cherokee County, Kansas, United States. The population was 101 at the 2000 census. The community was named after Louis Rose.[citation needed]

Contents

Geography

Roseland is located at 37°16′50″N 94°51′5″W / 37.28056°N 94.85139°W / 37.28056; -94.85139 (37.280671, -94.851489)[3].

According to the United States Census Bureau, the city has a total area of 0.8 square miles (2.1 km²), all of it land.

Roseland is on K-102, west of its junction with K-7.

Demographics

As of the census[1] of 2000, there were 101 people, 39 households, and 28 families residing in the city. The population density was 125.9 people per square mile (48.7/km²). There were 49 housing units at an average density of 61.1/sq mi (23.6/km²). The racial makeup of the city was 96.04% White, and 3.96% from two or more races.

There were 39 households out of which 30.8% had children under the age of 18 living with them, 51.3% were married couples living together, 10.3% had a female householder with no husband present, and 28.2% were non-families. 25.6% of all households were made up of individuals and 20.5% had someone living alone who was 65 years of age or older. The average household size was 2.59 and the average family size was 2.96.

In the city the population was spread out with 32.7% under the age of 18, 5.0% from 18 to 24, 29.7% from 25 to 44, 16.8% from 45 to 64, and 15.8% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 80.4 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the city was $25,000, and the median income for a family was $27,500. Males had a median income of $31,250 versus $12,917 for females. The per capita income for the city was $13,125. There were 11.1% of families and 10.3% of the population living below the poverty line, including 9.1% of under eighteens and 10.5% of those over 64.

References

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