Slaughterville, Oklahoma

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Slaughterville is a town in Cleveland County, Oklahoma, United States, located in and a part of the Oklahoma City metropolitan area. The population of Slaughterville was 3,609 at the 2000 census.



Slaughterville is located at 35°5′1″N 97°17′13″W / 35.08361°N 97.28694°W / 35.08361; -97.28694 (35.083584, -97.286945)[3].

According to the United States Census Bureau, the town has a total area of 38.3 square miles (99.1 km²), of which, 38.1 square miles (98.7 km²) of it is land and 0.2 square miles (0.4 km²) of it (0.39%) is water.


As of the census[1] of 2000, there were 3,609 people, 1,279 households, and 1,002 families residing in the town. The population density was 94.7 people per square mile (36.6/km²). There were 1,419 housing units at an average density of 37.2/sq mi (14.4/km²). The racial makeup of the town was 84.90% White, 0.69% African American, 5.60% Native American, 0.17% Asian, 0.08% Pacific Islander, 1.55% from other races, and 7.01% from two or more races. Hispanic or Latino of any race were 4.05% of the population.

There were 1,279 households out of which 39.2% had children under the age of 18 living with them, 63.2% were married couples living together, 11.0% had a female householder with no husband present, and 21.6% were non-families. 17.7% of all households were made up of individuals and 5.2% had someone living alone who was 65 years of age or older. The average household size was 2.78 and the average family size was 3.12.

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