St. Francis, Kansas

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St. Francis is the larger of two cities in and county seat of Cheyenne County, Kansas, United States.[3] As of the 2000 census, the city had a population of 1,497.

Contents

Geography

St. Francis is located at 39°46′17″N 101°48′3″W / 39.77139°N 101.80083°W / 39.77139; -101.80083 (39.771389, -101.800717)[4]. According to the United States Census Bureau, the city has a total area of 0.9 square miles (2.2 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 1,497 people, 669 households, and 426 families residing in the city. The population density was 1,771.2 people per square mile (680.0/km²). There were 766 housing units at an average density of 906.3/sq mi (347.9/km²). The racial makeup of the city was 97.80% White, 0.20% African American, 0.07% Native American, 0.47% Asian, 0.07% Pacific Islander, 0.53% from other races, and 0.87% from two or more races. Hispanic or Latino of any race were 2.27% of the population.

There were 669 households out of which 25.3% had children under the age of 18 living with them, 54.7% were married couples living together, 6.7% had a female householder with no husband present, and 36.2% were non-families. 34.8% of all households were made up of individuals and 20.8% had someone living alone who was 65 years of age or older. The average household size was 2.16 and the average family size was 2.76.

In the city the population was spread out with 21.7% under the age of 18, 6.1% from 18 to 24, 21.9% from 25 to 44, 18.9% from 45 to 64, and 31.4% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 91.2 males. For every 100 females age 18 and over, there were 83.4 males.

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