Sylvan Grove, Kansas

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Sylvan Grove is a city in Lincoln County, Kansas, United States. The population was 324 at the 2000 census.



Sylvan Grove is located at 39°0′46″N 98°23′33″W / 39.01278°N 98.3925°W / 39.01278; -98.3925 (39.012860, -98.392491)[3].

According to the United States Census Bureau, the city has a total area of 0.4 square miles (1.0 km²), all of it land.


As of the census[1] of 2000, there were 324 people, 157 households, and 88 families residing in the city. The population density was 876.5 people per square mile (338.1/km²). There were 195 housing units at an average density of 527.6/sq mi (203.5/km²). The racial makeup of the city was 96.91% White, 1.85% Native American, 0.93% from other races, and 0.31% from two or more races. Hispanic or Latino of any race were 1.54% of the population.

There were 157 households out of which 21.7% had children under the age of 18 living with them, 48.4% were married couples living together, 3.8% had a female householder with no husband present, and 43.9% were non-families. 40.8% of all households were made up of individuals and 24.8% had someone living alone who was 65 years of age or older. The average household size was 2.06 and the average family size was 2.82.

In the city the population was spread out with 21.0% under the age of 18, 4.9% from 18 to 24, 23.1% from 25 to 44, 23.5% from 45 to 64, and 27.5% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 98.8 males. For every 100 females age 18 and over, there were 98.4 males.

The median income for a household in the city was $27,188, and the median income for a family was $36,375. Males had a median income of $20,962 versus $16,250 for females. The per capita income for the city was $14,684. About 13.5% of families and 17.6% of the population were below the poverty line, including 27.4% of those under age 18 and 6.3% of those age 65 or over.

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