Wheatfield, Indiana

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Wheatfield is a town in Wheatfield Township, Jasper County, Indiana, United States. The population was 772 at the 2000 census.



Wheatfield is located at 41°11′29″N 87°03′09″W / 41.191376°N 87.052475°W / 41.191376; -87.052475.[3]

According to the United States Census Bureau, the town has a total area of 0.6 square miles (1.4 km²), all of it land.


As of the census[1] of 2000, there were 772 people, 267 households, and 191 families residing in the town. The population density was 1,398.4 people per square mile (541.9/km²). There were 289 housing units at an average density of 523.5/sq mi (202.9/km²). The racial makeup of the town was 94.17% White, 2.46% African American, 0.13% Asian, 0.78% from other races, and 2.46% from two or more races. Hispanic or Latino of any race were 2.46% of the population.

There were 267 households out of which 36.0% had children under the age of 18 living with them, 54.7% were married couples living together, 9.7% had a female householder with no husband present, and 28.1% were non-families. 24.3% of all households were made up of individuals and 8.2% had someone living alone who was 65 years of age or older. The average household size was 2.61 and the average family size was 3.07.

In the town the population was spread out with 33.2% under the age of 18, 9.5% from 18 to 24, 27.7% from 25 to 44, 18.5% from 45 to 64, and 11.1% who were 65 years of age or older. The median age was 29 years. For every 100 females there were 108.6 males. For every 100 females age 18 and over, there were 101.6 males.

The median income for a household in the town was $38,021, and the median income for a family was $43,750. Males had a median income of $34,792 versus $23,472 for females. The per capita income for the town was $15,003. About 6.1% of families and 7.5% of the population were below the poverty line, including 7.5% of those under age 18 and 5.0% of those age 65 or over.

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