Wheatland, Wyoming

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Wheatland is a town in and the county seat of Platte County in southeastern Wyoming, United States.[3] The population was 3,548 at the 2000 census.



Wheatland is located at 42°3′14″N 104°57′34″W / 42.05389°N 104.95944°W / 42.05389; -104.95944 (42.053917, -104.959460)[4].

According to the United States Census Bureau, the town has a total area of 4.2 square miles (11.0 km²), all land.


As of the census[1] of 2000, there were 3,548 people, 1,539 households, and 980 families residing in the town. The population density was 837.6 people per square mile (323.1/km²). There were 1,764 housing units at an average density of 416.4/sq mi (160.6/km²). The racial makeup of the town was 96.00% White, 0.31% African American, 0.68% Native American, 0.34% Asian, 1.89% from other races, and 0.79% from two or more races. Hispanic or Latino of any race were 6.54% of the population.

There were 1,539 households out of which 27.0% had children under the age of 18 living with them, 52.7% were married couples living together, 7.9% had a female householder with no husband present, and 36.3% were non-families. 32.2% of all households were made up of individuals and 16.8% had someone living alone who was 65 years of age or older. The average household size was 2.24 and the average family size was 2.83.

In the town the population was spread out with 22.8% under the age of 18, 7.2% from 18 to 24, 22.7% from 25 to 44, 26.5% from 45 to 64, and 20.8% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 89.5 males. For every 100 females age 18 and over, there were 88.8 males.

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